Theory of Structures For beams of uniform strength, if depth is constant, Width b 1/M Width b M Width b M 2 Width b 3 M Width b 1/M Width b M Width b M 2 Width b 3 M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good E = 3K (1 – 2/m) (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 2N (1 + 1/m) E = 3K (1 – 2/m) (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 2N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In plastic analysis, the shape factor for a triangular section, is 1.34 1.5 2.5 2.34 1.34 1.5 2.5 2.34 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A close coil helical spring of mean diameter D consists of n coils of diameter d. If it carries an axial load W, the energy stored in the spring, is 4W²D3n/d4N 4W²D3n²/d4N 4WD²n/d4N 4W²Dn/d4N 4W²D3n/d4N 4W²D3n²/d4N 4WD²n/d4N 4W²Dn/d4N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel bar 5 m × 50 mm is loaded with 250,000 N. If the modulus of elasticity of the material is 0.2 MN/mm² and Poisson’s ratio is 0.25, the change in the volume of the bar is: 2.125 cm³ 1.125 cm³ 3.125 cm³ 4.125 cm² 2.125 cm³ 1.125 cm³ 3.125 cm³ 4.125 cm² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 4h/l² × (1 – x) y = h/l² × (1 – x ) y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) y = 4h/l² × (1 – x) y = h/l² × (1 – x ) y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) ANSWER DOWNLOAD EXAMIANS APP
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