Electric Circuits For balanced star load, if unbalanced line current are IR, IY, IB equal to - j10, - j10 and - j20 respectively, the neutral current will be equal to (8.66 + j5) A. (-8.66 - j5) A. (-9.66 + j5) A. (8.66 - j5) A. (8.66 + j5) A. (-8.66 - j5) A. (-9.66 + j5) A. (8.66 - j5) A. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In above question, determine the current if E = 100 V, R = 20Ω, R1 = 10 Ω and L = 2 H at 0.5 sec after short circuit. - 6.28. 9.59. 6.98. - 9.59. - 6.28. 9.59. 6.98. - 9.59. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In the circuit shown below if I = 2 A then find V? 1 V. 2 V. 3 V. 5 V. 1 V. 2 V. 3 V. 5 V. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In a lead acid cell PbSO4 formed during discharging only. charging only. neither during charging nor discharging. both during charging as well as discharging. discharging only. charging only. neither during charging nor discharging. both during charging as well as discharging. ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits In given figure, the value of resistance R in Ω is 3.5 Ω 2.5 Ω 4.5 Ω 1 Ω 3.5 Ω 2.5 Ω 4.5 Ω 1 Ω ANSWER DOWNLOAD EXAMIANS APP
Electric Circuits Twelve 6 Ω resistor used as edge to form a cube. The resistance between two diagonally opposite corner of the cube is 5 / 6 Ω. 6 Ω. 5 Ω. 6 / 5 Ω. 5 / 6 Ω. 6 Ω. 5 Ω. 6 / 5 Ω. ANSWER DOWNLOAD EXAMIANS APP