Fractions and Decimals Find the value of 2 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)] 1200 1600 1400 800 1200 1600 1400 800 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 2 x [(3.6 x 0.48 x 2.50) / (0.12 x 0.09 x 0.5)]= 2 x [(36 x 48 x 250) / (12 x 9 x 5)]= 2 x 4 x 4 x 50 = 1600
Fractions and Decimals If 12276 / 155 = 79.2 the value of 122.76 / 15.5 is ? 0.792 79.2 792 7.92 0.792 79.2 792 7.92 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 122.76 / 15.50 = 12276/1550= (12276 / 155) x (1/10) = 79.2 / 10 = 7.92
Fractions and Decimals (.538 x .538 - .462 x .462) / (1-.924) = ? 31 21 1 11 31 21 1 11 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [ (.538)² - (.462)² ] / .076 = [(.538 + .462)(.538 - .462)] /.076=.076 / .076 = 1
Fractions and Decimals (1.04 x 1.04 + 1.04 x 0.04 + 0.04 x 0.04) / (1.04 x 1.04 x 1.04 - 0.04 x 0.04 x 0.04) = ? 3 2 0 1 3 2 0 1 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = (1.04)² + 1.04 x 0.04 + (0.04)² / (1.04)³ - (0.04)³= (a² + ab + b²) / (a³ - b³) = (a² + ab + b²) / [(a-b) (a² + ab + b²)]= 1 / (a - b)= 1/ (1.04 - 0.04) = 1
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2011 2012 2014 2013 2011 2012 2014 2013 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 1000.50 Rs. 10.50 Rs. 1.50 Rs. 100.50 Rs. 1000.50 Rs. 10.50 Rs. 1.50 Rs. 100.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
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