Problems on H.C.F and L.C.M Find the highest common factor of 36 and 84. 12 34 22 16 12 34 22 16 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 36 = 2² x 3²84 = 2² x 3 x 7H.C.F. = 2² x 3 = 12.
Problems on H.C.F and L.C.M LCM of 1/3, 5/6, 5/4, 10/7 is: 11/10 10 10/7 10/11 11/10 10 10/7 10/11 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What is the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder? 1245 1773 1650 1683 1245 1773 1650 1683 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ? 420 630 770 540 420 630 770 540 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 12, 18, 21, 30 2 | 12 - 18 - 21 - 30 ---------------------------- = 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15 ---------------------------- Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5 = 630.
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 8:27:12 hrs 7:25:14 hrs 10:13:17 hrs 9:22:08 hrs 8:27:12 hrs 7:25:14 hrs 10:13:17 hrs 9:22:08 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M If the sum of two numbers is 55 and the H.C.F and L.C.M of these numbers are 5 and 120 respectively, then the sum of the reciprocal of the numbers is equal to: 55/601 601/55 120/11 11/120 55/601 601/55 120/11 11/120 ANSWER DOWNLOAD EXAMIANS APP
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