Since the difference between the divisors and the respective remainders is not constant, back substitution is the convenient method. None of the given numbers is satisfying the condition.
If the sum of the digits of a number is divisible by 9, the number will be divisible by 9.2 + 6 + 3 + 2 + 5 + 1 = 19The nearest multiple of 9 is 18.19 - 18 = 1.