Let 'N' is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.Required number = (LCM of 13 and 16) - (common difference of divisors and remainders) = (208) - (11) = 197.
Let the two consecutive odd numbers be 2x - 1 and 2x + 1.(2x - 1) (2x - 1) = 4095= 4x² - 1 = 4095= 4x² = 4096= x² = 1024∴ x = 32∴ The numbers are 63 and 65.Greater number = 65
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