DNA Structure and Replication Enzymes, responsible for unraveling short segments of DNA is DNA ligase primase DNA polymerase helicase DNA ligase primase DNA polymerase helicase ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Nucleosome is an hexamer of three histones without H1 protein an octamer of four histones with H1 protein an hexamer of three histones with H1 protein an octamer of four histones without H1 protein an hexamer of three histones without H1 protein an octamer of four histones with H1 protein an hexamer of three histones with H1 protein an octamer of four histones without H1 protein ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication The overall conclusion of the Hershey-Chase experiment was that DNA was responsible for heredity proteins and DNA were responsible for heredity the ratio of Adenine to thymine was always the same phage DNA was similar to bacterial DNA DNA was responsible for heredity proteins and DNA were responsible for heredity the ratio of Adenine to thymine was always the same phage DNA was similar to bacterial DNA ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Which of the following is an active site on its single polypeptide chain for DNA Polymerase I? 3' → 5' exonuclease 5' → 3' polymerase 5' → 3' exonuclease All of these 3' → 5' exonuclease 5' → 3' polymerase 5' → 3' exonuclease All of these ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Which of the following species lack a 'classical' histone H1? Xenopus laevis Arabidopsis thaliana Strongylocentrotus purpuratus Saccharomyces cerevisiae Xenopus laevis Arabidopsis thaliana Strongylocentrotus purpuratus Saccharomyces cerevisiae ANSWER DOWNLOAD EXAMIANS APP
DNA Structure and Replication Which of the following is used to determine the appropriate stringency (Wallace rule)? Tm = 69.3° + 0.41 (%)G+C -650/1 Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) Tm = 69.3° + 0.41 (%)G+C -650/1 Tm = 4 x (No.of A:T base pair) + 2 x (No.of G:C base pair) Tm = 2 x (No.of G:C base pair) + 4 x (No.of A:T base pair) Tm = 4 x (No.of G:C base pair) + 2 x (No.of A:T base pair) ANSWER DOWNLOAD EXAMIANS APP
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