Hydraulics and Fluid Mechanics in ME Discharge of a centrifugal pump is (where N = Speed of the pump impeller) Directly proportional to N² Inversely proportional to N² Inversely proportional to N Directly proportional to N Directly proportional to N² Inversely proportional to N² Inversely proportional to N Directly proportional to N ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A square surface 3 m x 3 m lies in a vertical line in water pipe its upper edge at vater surface. The hydrostatic force on square surface is 18,000 kg 27,000 kg 13,500 kg 9,000 kg 18,000 kg 27,000 kg 13,500 kg 9,000 kg ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a small rectangular orifice is given by (where Cd = Coefficient of discharge for the orifice, a = Cross-sectional area of the orifice, h = Height of the liquid above the centre of the orifice) Q = (Cd × a)/√(2gh) Q = Cd × a × 2gh Q = (2/3). Cd × a × h Q = (3Cd × a)/√(2h) Q = (Cd × a)/√(2gh) Q = Cd × a × 2gh Q = (2/3). Cd × a × h Q = (3Cd × a)/√(2h) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The total energy of a liquid particle in motion is equal to Potential energy - (pressure energy + kinetic energy Pressure energy - (kinetic energy + potential energy) Pressure energy + kinetic energy + potential energy Kinetic energy - (pressure energy + potential energy) Potential energy - (pressure energy + kinetic energy Pressure energy - (kinetic energy + potential energy) Pressure energy + kinetic energy + potential energy Kinetic energy - (pressure energy + potential energy) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a large rectangular orifice is given by (where H1 = Height of the liquid above the top of the orifice, H2 = Height of the liquid above the bottom of the orifice, b = Breadth of the orifice, and Cd = Coefficient of discharge) Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2) Q = (2/3) Cd × b × √(2g) × (H22 - H12) Q = (2/3) Cd × b × √(2g) × (H2 - H1) Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2) Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2) Q = (2/3) Cd × b × √(2g) × (H22 - H12) Q = (2/3) Cd × b × √(2g) × (H2 - H1) Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Euler's equation in the differential form for the motion of liquids is given by dp/ρ - g.dz + v.dv = 0 ρ.dp + g.dz + v.dv = 0 ρ.dp - g.dz + v.dv = 0 dp/ρ + g.dz + v.dv = 0 dp/ρ - g.dz + v.dv = 0 ρ.dp + g.dz + v.dv = 0 ρ.dp - g.dz + v.dv = 0 dp/ρ + g.dz + v.dv = 0 ANSWER DOWNLOAD EXAMIANS APP
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