Current through the 10Ω resistance I1 = V/R = 20/10 = 2A I1 = 2A Now current through the 20Ω resistance I2 = V − (-10)/R = 20 + 10/30 = 1.5 A I2 = 1.5 A
The resistance of the conductor is determined by the R = ρL/A Where ρ = Resistivity of the conductor L = Length of the conductor = 10 m A = Area of the conductor = πR2 = 3.14 × 0.22 = 0.125 m2 R = Resistance = 2 Ω Therefore the resistivity is ρ = A × R ⁄ L = 0.125 × 2 ⁄ 10 ρ = 0.025 Ω-m
According to Kirchhoff’s Current Law: At any point in an electrical circuit, the sum of currents flowing towards that point is equal to the sum of currents flowing away from that point. ∴ I1 = 1 + 3 = 4A V = IR ∴ V1 = I1R = 8 × 4 V1 = 32Ω
EXAMIANS
