C Programming Determine Output:void main(){ int i=0, j=0; if(i && j++) printf("%d..%d", i++, j); printf("%d..%d", i, j);} 0..1 1..1 0..0 1..0 0..1 1..1 0..0 1..0 ANSWER DOWNLOAD EXAMIANS APP
C Programming short testarray[4][3] = { {1}, {2,3}, {4,5,6}};printf("%d", sizeof(testarray));Assuming a short is two bytes long, what will be printed by the above code? 6 7 12 It will not compile because not enough initializers are given 24 6 7 12 It will not compile because not enough initializers are given 24 ANSWER DOWNLOAD EXAMIANS APP
C Programming If integer needs two bytes of storage, then maximum value of an unsigned integer is None of these 215 – 1 215 216 216 – 1 None of these 215 – 1 215 216 216 – 1 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char *str1 = "abcd"; char str2[] = "abcd"; printf("%d %d %d", sizeof(str1), sizeof(str2), sizeof("abcd"));} 2 4 4 5 5 5 2 4 5 2 5 5 2 4 4 5 5 5 2 4 5 2 5 5 ANSWER DOWNLOAD EXAMIANS APP
C Programming Consider the following code:void main(){ int a[5] = {6,8,3,9,0}, i=0; if(i != 0) { break; printf("%d", a[i]); } else printf("%d", a[i++]);}What is the output of the above program? Syntax error Runtime error 8 No output 6 Syntax error Runtime error 8 No output 6 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine output:#include void main(){ char *p = NULL; char *q = 0; if(p) printf(" p "); else printf("nullp"); if(q) printf("q"); else printf(" nullq");} x nullq where x can be p or nullp depending on the value of NULL p q nullp nullq Depends on the compiler x nullq where x can be p or nullp depending on the value of NULL p q nullp nullq Depends on the compiler ANSWER DOWNLOAD EXAMIANS APP
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