C Programming Determine Output:void main(){ int i=0, j=0; if(i && j++) printf("%d..%d", i++, j); printf("%d..%d", i, j);} 0..1 0..0 1..1 1..0 0..1 0..0 1..1 1..0 ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be printed if the following code is executed?void main(){ int x=0; for( ; ; ) { if( x++ == 4 ) break; continue; } printf("x=%d", x);} x=1 x=5 x=0 Error x=4 x=1 x=5 x=0 Error x=4 ANSWER DOWNLOAD EXAMIANS APP
C Programming short testarray[4][3] = { {1}, {2,3}, {4,5,6}};printf("%d", sizeof(testarray));Assuming a short is two bytes long, what will be printed by the above code? 24 7 6 12 It will not compile because not enough initializers are given 24 7 6 12 It will not compile because not enough initializers are given ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output?main() { char *p; p = "Hello"; printf("%cn",*&*p); } Some address will be printed None of these. Hello H Some address will be printed None of these. Hello H ANSWER DOWNLOAD EXAMIANS APP
C Programming Which of the following comments about the ++ operator are correct? It is a unary operator All of these It associates from the right It cannot be applied to an expression The operand can come before or after the operator It is a unary operator All of these It associates from the right It cannot be applied to an expression The operand can come before or after the operator ANSWER DOWNLOAD EXAMIANS APP
C Programming The address operator &, cannot act on Arithmetic expressions R-values Local variables Members of a structure Both of the above Arithmetic expressions R-values Local variables Members of a structure Both of the above ANSWER DOWNLOAD EXAMIANS APP