C Programming Determine Output:void main(){ int i=5, j=6, z; printf("%d", i+++j);} 13 12 None of These 11 13 12 None of These 11 ANSWER DOWNLOAD EXAMIANS APP
C Programming What is the output of given program if user enter value 99?#includevoid main(){int i;printf("Enter a number:");scanf("%d", &i); // 99 is given as input.if(i%5 == 0){printf("nNumber entered is divisible by 5"); }} complier error Enter a number:99 Number is divisible by 5 Enter a number:99 Run time error complier error Enter a number:99 Number is divisible by 5 Enter a number:99 Run time error ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the program if the array begins at address 65486?#includevoid main(){ int arr[] = {12, 14, 15, 23, 45}; printf("%u, %u", arr, &arr);} 65486, 65490 65486, 65488 None of these 65486, 65487 65486, 65486 65486, 65490 65486, 65488 None of these 65486, 65487 65486, 65486 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:#includevoid main(){ register i=5; char j[]= "hello"; printf("%s %d", j, i);} None of These hello 5 Error hello garbage value None of These hello 5 Error hello garbage value ANSWER DOWNLOAD EXAMIANS APP
C Programming What is the right choice, if the following loop is implemented?void main(){ int num = 0; do{ --num; printf("%d", num); }while( ++num >= 0 );} There will be a compilation error reported. The loop will run infinitely many times. Prints the value of 0 one time only. A run time error will be generated. The program will not enter into the loop. There will be a compilation error reported. The loop will run infinitely many times. Prints the value of 0 one time only. A run time error will be generated. The program will not enter into the loop. ANSWER DOWNLOAD EXAMIANS APP
C Programming Consider the following code:void main(){ int a[5] = {6,8,3,9,0}, i=0; if(i != 0) { break; printf("%d", a[i]); } else printf("%d", a[i++]);}What is the output of the above program? Runtime error No output 6 Syntax error 8 Runtime error No output 6 Syntax error 8 ANSWER DOWNLOAD EXAMIANS APP
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