C Programming Determine Output:void main(){ float me = 1.1; double you = 1.1; if(me==you) printf("I hate Examveda"); else printf("I love Examveda");} None of These I love Examians Error I hate Examians None of These I love Examians Error I hate Examians ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ int c[] = {2.8,3.4,4,6.7,5}; int j, *p=c, *q=c; for(j=0;j<5;j++){ printf(" %d ", *c); ++q; } for(j=0;j<5;j++){ printf(" %d ", *p); ++p; }} 2 3 4 6 5 2 3 4 6 5 2 2 2 2 2 2 3 4 6 5 2.8 3.4 4 6.7 5 2.8 3.4 4 6.7 2.8 2.8 2.8 2.8 2.8 2.8 3.4 4 2 3 4 6 5 2 3 4 6 5 2 2 2 2 2 2 3 4 6 5 2.8 3.4 4 6.7 5 2.8 3.4 4 6.7 2.8 2.8 2.8 2.8 2.8 2.8 3.4 4 ANSWER DOWNLOAD EXAMIANS APP
C Programming The address operator &, cannot act on Both of the above R-values Arithmetic expressions Local variables Members of a structure Both of the above R-values Arithmetic expressions Local variables Members of a structure ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char not; not = !2; printf("%d", not);} None of These Garbage Value 0 2 None of These Garbage Value 0 2 ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be printed if the following code is executed?void main(){ int x=0; for( ; ; ) { if( x++ == 4 ) break; continue; } printf("x=%d", x);} x=1 x=0 Error x=4 x=5 x=1 x=0 Error x=4 x=5 ANSWER DOWNLOAD EXAMIANS APP
C Programming A function 'p' that accepts a pointer to a character as argument and returns a pointer to an array of integer can be declared as int(*p(char *))[] None of these. int (*p) (char *)[] int *p(char *)[] int(*p(char *))[] None of these. int (*p) (char *)[] int *p(char *)[] ANSWER DOWNLOAD EXAMIANS APP
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