C Programming Determine Output:void main(){ char *str1 = "abcd"; char str2[] = "abcd"; printf("%d %d %d", sizeof(str1), sizeof(str2), sizeof("abcd"));} 2 4 4 2 4 5 5 5 5 2 5 5 2 4 4 2 4 5 5 5 5 2 5 5 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ static char *s[] = {"black", "white", "yellow", "violet"}; char **ptr[] = {s+3, s+2, s+1, s}, ***p; p = ptr; ++p; printf("%s",*--*++p + 3); } et ck ow te et ck ow te ANSWER DOWNLOAD EXAMIANS APP
C Programming The type of the controlling expression of a switch statement cannot be of the type ........ int long short float char int long short float char ANSWER DOWNLOAD EXAMIANS APP
C Programming The declarationint (*p) [5];means None of these. The same as int *p[ p is a pointer to a 5 elements integer array. p is one dimensional array of size 5, of pointers to integers. None of these. The same as int *p[ p is a pointer to a 5 elements integer array. p is one dimensional array of size 5, of pointers to integers. ANSWER DOWNLOAD EXAMIANS APP
C Programming Comment on the following pointer declaration?int *ptr, p; ptr and p, both are pointers to integer. ptr is a pointer to integer, p is not. ptr and p both are not pointers to integer. ptr is pointer to integer, p may or may not be. ptr and p, both are pointers to integer. ptr is a pointer to integer, p is not. ptr and p both are not pointers to integer. ptr is pointer to integer, p may or may not be. ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ int i=0; for(;i++;printf("%d", i)); printf("%d", i);} 12 1 Error 11 12 1 Error 11 ANSWER DOWNLOAD EXAMIANS APP
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