C Programming Find the output of the following program.#includevoid main(){ int y=10; if(y++>9 && y++!=10 && y++>11) printf("%d", y); else printf("%d", y);} 14 11 Compilation error 12 13 14 11 Compilation error 12 13 ANSWER DOWNLOAD EXAMIANS APP
C Programming In an expression involving || operator, evaluationI. Will be stopped if one of its components evaluates to falseII. Will be stopped if one of its components evaluates to trueIII. Takes place from right to leftIV. Takes place from left to right II and III I and II I and III II and IV III and IV II and III I and II I and III II and IV III and IV ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ float me = 1.1; double you = 1.1; if(me==you) printf("I hate Examveda"); else printf("I love Examveda");} None of These I hate Examians I love Examians Error None of These I hate Examians I love Examians Error ANSWER DOWNLOAD EXAMIANS APP
C Programming Consider the following code:void main(){ int a[5] = {6,8,3,9,0}, i=0; if(i != 0) { break; printf("%d", a[i]); } else printf("%d", a[i++]);}What is the output of the above program? Runtime error No output 8 6 Syntax error Runtime error No output 8 6 Syntax error ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:#includevoid main(){ char s[]={'a','b','c','n','c','\0'}; char *p, *str, *str1; p=&s[3]; str=p; str1=s; printf("%c", ++*p + ++*str1-32);} P None of These N M P None of These N M ANSWER DOWNLOAD EXAMIANS APP
C Programming Comment on the following pointer declaration?int *ptr, p; ptr and p both are not pointers to integer. ptr and p, both are pointers to integer. ptr is a pointer to integer, p is not. ptr is pointer to integer, p may or may not be. ptr and p both are not pointers to integer. ptr and p, both are pointers to integer. ptr is a pointer to integer, p is not. ptr is pointer to integer, p may or may not be. ANSWER DOWNLOAD EXAMIANS APP
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