C Programming Determine output:main(){ int i = 5; printf("%d%d%d%d%d", i++, i--, ++i, --i, i);} 45445 54544 54554 45545 45445 54544 54554 45545 ANSWER DOWNLOAD EXAMIANS APP
C Programming What is the output of the following statements?int i = 0;printf("%d %d", i, i++); 1 1 1 0 0 1 None of these 0 0 1 1 1 0 0 1 None of these 0 0 ANSWER DOWNLOAD EXAMIANS APP
C Programming String concatenation means - Partitioning the string into two strings. Extracting a substring out of a string. Merging two strings. Combining two strings. Comparing the two strings to define the larger one. Partitioning the string into two strings. Extracting a substring out of a string. Merging two strings. Combining two strings. Comparing the two strings to define the larger one. ANSWER DOWNLOAD EXAMIANS APP
C Programming Consider the following code:void main(){ int a[5] = {6,8,3,9,0}, i=0; if(i != 0) { break; printf("%d", a[i]); } else printf("%d", a[i++]);}What is the output of the above program? No output 8 6 Syntax error Runtime error No output 8 6 Syntax error Runtime error ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char string[]="Hello World"; display(string);}void display(char *string){ printf("%s", string);} Can't Say Compiler Error None of These will print Hello World Can't Say Compiler Error None of These will print Hello World ANSWER DOWNLOAD EXAMIANS APP
C Programming What would be the output for the following Turbo C code?#includevoid main(){ int a[]={ 1, 2, 3, 4, 5 }, *p; p=a; ++*p; printf("%d ", *p); p += 2; printf("%d", *p);} 2 3 3 3 2 4 2 2 3 4 2 3 3 3 2 4 2 2 3 4 ANSWER DOWNLOAD EXAMIANS APP
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