C Programming Determine output:main(){ int i = 5; printf("%d%d%d%d%d", i++, i--, ++i, --i, i);} 54554 54544 45445 45545 54554 54544 45445 45545 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char *p="hi friends", *p1; p1=p; while(*p!='\0') ++*p++; printf("%s", p1);} hi friends ij!gsjfoet hj grjeodt None of These hi friends ij!gsjfoet hj grjeodt None of These ANSWER DOWNLOAD EXAMIANS APP
C Programming Find the output of the following program.void main(){ printf("%d, %d", sizeof(int *), sizeof(int **));} 2, 2 4, 4 0, 2 2, 4 2, 0 2, 2 4, 4 0, 2 2, 4 2, 0 ANSWER DOWNLOAD EXAMIANS APP
C Programming A function 'p' that accepts a pointer to a character as argument and returns a pointer to an array of integer can be declared as int *p(char *)[] None of these. int(*p(char *))[] int (*p) (char *)[] int *p(char *)[] None of these. int(*p(char *))[] int (*p) (char *)[] ANSWER DOWNLOAD EXAMIANS APP
C Programming Comment on the following pointer declaration?int *ptr, p; ptr and p both are not pointers to integer. ptr is pointer to integer, p may or may not be. ptr and p, both are pointers to integer. ptr is a pointer to integer, p is not. ptr and p both are not pointers to integer. ptr is pointer to integer, p may or may not be. ptr and p, both are pointers to integer. ptr is a pointer to integer, p is not. ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine output:main(){ int i = abc(10); printf("%d", --i);}int abc(int i){ return(i++);} 10 11 9 None of these. 10 11 9 None of these. ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS