C Programming Find the output of the following program.void main(){ printf("%d, %d", sizeof(int *), sizeof(int **));} 2, 2 0, 2 2, 0 2, 4 4, 4 2, 2 0, 2 2, 0 2, 4 4, 4 ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of following program code?#include int main(void){ char p; char buf[10] = {1, 2, 3, 4, 5, 6, 9, 8}; p = (buf + 1)[5]; printf("%d", p); return 0;} 5 9 Error None of these 6 5 9 Error None of these 6 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ static int var = 5; printf("%d ", var--); if(var) main();} 5 5 5 5 5 Infinite Loop None of These 5 4 3 2 1 5 5 5 5 5 Infinite Loop None of These 5 4 3 2 1 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:#includevoid main(){ char s[]={'a','b','c','n','c','\0'}; char *p, *str, *str1; p=&s[3]; str=p; str1=s; printf("%c", ++*p + ++*str1-32);} M P None of These N M P None of These N ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char *str1 = "abcd"; char str2[] = "abcd"; printf("%d %d %d", sizeof(str1), sizeof(str2), sizeof("abcd"));} 2 5 5 2 4 4 5 5 5 2 4 5 2 5 5 2 4 4 5 5 5 2 4 5 ANSWER DOWNLOAD EXAMIANS APP
C Programming Comment on the following pointer declaration?int *ptr, p; ptr and p, both are pointers to integer. ptr is pointer to integer, p may or may not be. ptr is a pointer to integer, p is not. ptr and p both are not pointers to integer. ptr and p, both are pointers to integer. ptr is pointer to integer, p may or may not be. ptr is a pointer to integer, p is not. ptr and p both are not pointers to integer. ANSWER DOWNLOAD EXAMIANS APP
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