Chemical Engineering Thermodynamics Cp of a gas at its critical temperature and pressure Becomes zero Becomes infinity Equals 1 kcal/kmol °K Equals 0.24 kcal/kmol °K Becomes zero Becomes infinity Equals 1 kcal/kmol °K Equals 0.24 kcal/kmol °K ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Claussius-Clayperon equation gives accurate result, when the Vapour obeys the ideal gas law and the latent heat of vaporisation is constant All of these Vapour pressure is relatively low and the temperature does not vary over wide limits Volume in the liquid state is negligible compared with that in the vapour state Vapour obeys the ideal gas law and the latent heat of vaporisation is constant All of these Vapour pressure is relatively low and the temperature does not vary over wide limits Volume in the liquid state is negligible compared with that in the vapour state ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Boiling of liquid is accompanied with increase in the All of these Specific Gibbs free energy Vapor pressure Specific entropy All of these Specific Gibbs free energy Vapor pressure Specific entropy ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics With increase in temperature, the internal energy of a substance Increases May increase or decrease; depends on the substance Decreases Remains unchanged Increases May increase or decrease; depends on the substance Decreases Remains unchanged ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics The accentric factor of a materical, 'ω', is defined as ω = -log10(Prsat)Tr⁻¹ = 0.7, where, Prsat = reduced vapor pressure, Tr = reduced temperature. The value of accentric factor is always < 1 > 1 > 2 < 3 < 1 > 1 > 2 < 3 ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Joule-Thomson co-efficient depends on the Pressure Both A & B Temperature Neither A nor B Pressure Both A & B Temperature Neither A nor B ANSWER DOWNLOAD EXAMIANS APP
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