Applied Mechanics and Graphic Statics Cartesian form of the equation of catenary is y = c cosh x/c y = c tan x/c y = c sinh x/c y = c sin x/c y = c cosh x/c y = c tan x/c y = c sinh x/c y = c sin x/c ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces has the same magnitude as either of the force, then the angle between the two forces is 60° 120° 45° 30° 60° 120° 45° 30° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces ‘P’ and ‘Q’ acting at an angle ‘θ’, is √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ √(P² + Q² + 2PQ cos θ) P² + Q² + 2PQ cos θ P² + Q² + 2PQ tan θ P² + Q² + 2P sin θ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A weight of 100 kg is supported by a string whose ends are attached to pegs ‘A’ and ‘B’ at the same level shown in below figure. The tension in the string is 750 kg 100 kg 120 kg 50 kg 750 kg 100 kg 120 kg 50 kg ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball is dropped from a height of 2.25 m on a smooth floor and rises to a height of 1.00 m after the bounce. The coefficient of restitution between the ball and the floor is 0.33 0.44 0.57 0.67 0.33 0.44 0.57 0.67 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ ANSWER DOWNLOAD EXAMIANS APP
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