Applied Mechanics and Graphic Statics Cartesian form of the equation of catenary is y = c sin x/c y = c tan x/c y = c sinh x/c y = c cosh x/c y = c sin x/c y = c tan x/c y = c sinh x/c y = c cosh x/c ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A rod 5 m in length is moving in a vertical plane. When it is inclined at 60° to horizontal, its lower end is moving horizontally at 3 m/sec and upper end is moving in vertical direction. The velocity of its upper end, is 1.0 m/sec 0.5 m/sec 2.5 m/sec 1.5 m/sec 1.0 m/sec 0.5 m/sec 2.5 m/sec 1.5 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If ‘α’ is the angular acceleration of a compound pendulum whose angular displacement is ‘θ’, the frequency of the motion is 2π √(α - θ) 4π √(α/θ) (1/2π) √(α/θ) 2π √(α/θ) 2π √(α - θ) 4π √(α/θ) (1/2π) √(α/θ) 2π √(α/θ) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If y is force and x is velocity, then dimensions of —=r are dx2 M’^T’ M2L’T3 M’L-‘T1 M’L-‘T0 M’^T’ M2L’T3 M’L-‘T1 M’L-‘T0 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone was thrown vertically upwards from the ground with a velocity of 50 m/sec. After 5 seconds another stone was thrown vertically upwards from the same place. If both the stones strike the ground at the same time, then the velocity with which the second stone was thrown should be (Assume g = 10 m/sec²) 25 m/sec 40 m/sec 15 m/sec 50 m/sec 25 m/sec 40 m/sec 15 m/sec 50 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The centre of gravity of the trapezium as shown in below figure from the side is at a distance of (h/3) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] (h/3) × [(2b + a)/(b + a)] (h/3) × [(b + 2a)/(b + a)] (h/2) × [(2b + a)/(b + a)] (h/2) × [(b + 2a)/(b + a)] ANSWER DOWNLOAD EXAMIANS APP
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