Applied Mechanics and Graphic Statics Cartesian form of the equation of catenary is y = c cosh x/c y = c sin x/c y = c sinh x/c y = c tan x/c y = c cosh x/c y = c sin x/c y = c sinh x/c y = c tan x/c ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Time period and length of a second’s pendulum respectively are 2 sec and 92.7 cm 1 sec and 99.4 cm 2 sec and 99.4 cm 1 sec and 92.7 cm 2 sec and 92.7 cm 1 sec and 99.4 cm 2 sec and 99.4 cm 1 sec and 92.7 cm ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The resultant of two forces acting at right angles is 5 kgf and if they act at an angle of 60°, it is 37 kgf. The magnitudes of the forces are: 5 kgf, 3 kgf 2 kgf, 3 kgf 4 kgf, 5 kgf 3 kgf, 4 kgf 5 kgf, 3 kgf 2 kgf, 3 kgf 4 kgf, 5 kgf 3 kgf, 4 kgf ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The height at which the end of a rope of length ‘l’ should be tied so that a man pulling at the other end may have the greatest tendency to overturn the pillar, is ¾ l ½ l 2/√3 l l/√2 ¾ l ½ l 2/√3 l l/√2 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Ball ‘A’ of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/s hits an identical stationary ball ‘B’ on the table. If the impact is perfectly elastic, the velocity of the ball ‘B’ just after impact would be 10 m/sec 5 m/sec Zero None of these 10 m/sec 5 m/sec Zero None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A 2 m long ladder rests against a wall and makes an angle of 30° with the horizontal floor. Where will be the instantaneous center of rotation when the ladder starts slipping ?i. 1.0 in from the wallii. 1.732 m from the walliii. 1.0 m above the flooriv. 1.732 m above the floorThe correct answer is (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) (i) and (iii) (ii) and (iv) (ii) and (iii) (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
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