Calculate the phase angle between the voltage and current phasor of a series RL circuit having the resistance of 65 Ohms and Inductive reactance of 37.53 ohms when supplied by a frequency of 60 Hz

• A. 60°
• B. 30°
• C. 45°
• D. 15°

Answer: (B)

The phase angle θ of a series RL circuit is given as
θ = tan−1(XL ⁄ R)
Where
XL = Inductive Reactance = 37.53
R = Resistance = 65
θ = tan−1(37.53 ⁄ 65)
θ = tan−1(0.57)
θ = 30°