Fractions and Decimals By how much is 12% of 24.2 more than 10% of 14.2 ? 1.484 1.884 1.684 1.284 1.484 1.884 1.684 1.284 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required difference = (12 x 24.2) / 100 - (10 x 14.2) / 100= 2.904 -1.42 = 1.484
Fractions and Decimals Out of the fractions 4/7, 5/13, 6/11, 3/5 and 2/3 which is the second smallest fraction ? 4/7 3/5 6/11 5/13 4/7 3/5 6/11 5/13 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 4/7 = 0.57, 5/13 = 0.38, 6/11 = 0.54, 3/5 = 0.6 and 2/3 = 0.67Clearly, the second smallest fraction is 6/11
Fractions and Decimals [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] = ? 10000 100 100000 1000 10000 100 100000 1000 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(0.05)² + (0.41)² +(0.073)²] / [(0.005)² + (0.041)² + (0.0073)²] Which is in form of [(a² + b² + c²)] /[ (a/10)² + (b/10)² + (c/10)²] = 100 x (a² + b² + c²) / (a²+b²+c²) = 100
Fractions and Decimals 5 x 0.25 x 6.301 x 0.00394=? 3.10324250 0.310324250 0.0310324250 31.0324250 3.10324250 0.310324250 0.0310324250 31.0324250 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Here 5 x 25 x 6301 x 394=310324250Total decimal places = (2+3+5) = 10 ∴ 5 x 0.25 x 6.301 x 0.00394 = 0.0310324250
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2014 2011 2012 2013 2014 2011 2012 2013 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals If x/y = 0.3, then (2x - y)/(2x + y) = ? 0.5 0.5 0.15 0.25 0.5 0.5 0.15 0.25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP x = 0.3y Then, (y - 2x)/(y + 2x)= y - 2(0.3y)/y + 2(0.3y)= y - 0.6y/y + 0.6y= 0.4y/1.6y= 0.4/1.6 = 0.25
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