Fluid Mechanics Boundary layer thickness in turbulent flow over a flat plate increases as(where, d = distance from the leading edge.) d1/3 d2/3 √d d4/5 d1/3 d2/3 √d d4/5 ANSWER DOWNLOAD EXAMIANS APP
Fluid Mechanics The terminal velocity of a solid spherical particle falling through a stationary fluid mass in the Stoke's law range is proportional to the Inverse of fluid viscosity Square of particle size All of these Difference in the densities of the particle & fluid Inverse of fluid viscosity Square of particle size All of these Difference in the densities of the particle & fluid ANSWER DOWNLOAD EXAMIANS APP
Fluid Mechanics A double acting reciprocating pump compared to a single acting pump (of almost same size working under same pressure levels) would give almost double None of these Efficiency Discharge Head None of these Efficiency Discharge Head ANSWER DOWNLOAD EXAMIANS APP
Fluid Mechanics Pressure drop (Δp) for a fluid flowing in turbulent flow through a pipe is a function of velocity (V) as V2.7 V-0.2 V2 V1.8 V2.7 V-0.2 V2 V1.8 ANSWER DOWNLOAD EXAMIANS APP
Fluid Mechanics A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle system (in SI units) is given below : Δ P/L = 375 x 10³ VOM + 10.94 x 10⁶ V²OM (SI units) If water is to be used as the fluidising medium, the minimum fluidisation velocity, VOM is 24 mm/s 12 mm/s 16 mm/s 28 mm/s 24 mm/s 12 mm/s 16 mm/s 28 mm/s ANSWER DOWNLOAD EXAMIANS APP
Fluid Mechanics The equation given below is called the __________ . f-0.5 = 4.07 loge (NRe√f)-0.6 Fanning equation None of these Von-Karman equation Colebrook formula Fanning equation None of these Von-Karman equation Colebrook formula ANSWER DOWNLOAD EXAMIANS APP
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