Machine Design Belt slip may occur due to All of these Heavy load Loose belt Driving pulley too small All of these Heavy load Loose belt Driving pulley too small ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design For tight leakage joints, following type of thread is best suited Buttress Square NPT (national pipe threads). Metric Buttress Square NPT (national pipe threads). Metric ANSWER DOWNLOAD EXAMIANS APP
Machine Design If T₁ and T₂ are the tensions on the tight and slack sides of the belt respectively, and Tc is the centrifugal tension, then initial tension in the belt is equal to (T₁ + T₂ + Tc)/2 T₁ - T₂ + Tc (T₁ - T₂ + Tc)/2 T₁ + T₂ + Tc (T₁ + T₂ + Tc)/2 T₁ - T₂ + Tc (T₁ - T₂ + Tc)/2 T₁ + T₂ + Tc ANSWER DOWNLOAD EXAMIANS APP
Machine Design The design of the pressure vessel is based on Longitudinal and hoop stress Hoop stress Longitudinal stress None of these Longitudinal and hoop stress Hoop stress Longitudinal stress None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design A bolt is designed on the basis of __________ with a large factor of safety. Direct shear stress Direct bending stress Direct compressive stress Direct tensile stress Direct shear stress Direct bending stress Direct compressive stress Direct tensile stress ANSWER DOWNLOAD EXAMIANS APP
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