Machine Design Belt slip may occur due to Heavy load All of these Loose belt Driving pulley too small Heavy load All of these Loose belt Driving pulley too small ANSWER DOWNLOAD EXAMIANS APP
Machine Design A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is τ. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be τ 4 τ τ/2 2 τ τ 4 τ τ/2 2 τ ANSWER DOWNLOAD EXAMIANS APP
Machine Design A plate with an elliptical hole in the centre, with semi-major axis (a) perpendicular to the direction of loading and semi-minor axis (b) along the direction of loading, is subjected to a pull P. The maximum stress induced at the edge of the hole is equal to (where σ = Stress for a plate with no hole i.e. nominal stress) σ [1 + (2a/b)] σ [1 + (3a/b)] σ [1 + (b/2a)] σ [1 + (b/3a)] σ [1 + (2a/b)] σ [1 + (3a/b)] σ [1 + (b/2a)] σ [1 + (b/3a)] ANSWER DOWNLOAD EXAMIANS APP
Machine Design The bending moment ‘M’ and a torque ‘T’ is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then ‘M’ is equal to 4 T 1 T T/2 2 T 4 T 1 T T/2 2 T ANSWER DOWNLOAD EXAMIANS APP
Machine Design Stress concentration is caused due to Abrupt change of section Variation in properties of material from point to point in a member All of these Pitting at points or areas at which loads on a member are applied Abrupt change of section Variation in properties of material from point to point in a member All of these Pitting at points or areas at which loads on a member are applied ANSWER DOWNLOAD EXAMIANS APP
Machine Design If d is the normal diameter of a bolt in mm, then the initial tension in kg in a bolt used for making a fluid tight joint as for steam engine cover joint is calculated by the relation 124 d 138 d 151 d 168 d 124 d 138 d 151 d 168 d ANSWER DOWNLOAD EXAMIANS APP
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