Machine Design Applications in which stresses are encountered in one direction only uses following type of threads Acme Buttress Square Metric Acme Buttress Square Metric ANSWER DOWNLOAD EXAMIANS APP
Machine Design When the connected members are very yielding (soft gasket) as compared to the bolt, then the resultant load on the bolt will be equal to the External load applied Sum of the initial tension and external load applied Initial tension or external load, whichever is greater Initial tension External load applied Sum of the initial tension and external load applied Initial tension or external load, whichever is greater Initial tension ANSWER DOWNLOAD EXAMIANS APP
Machine Design When a shaft is subjected to combined twisting moment (T) and bending moment (M), then the equivalent twisting moment is equal to (1/2) × √(M² + T²) (1/2) × [M + √(M² + T²)] M + √(M² + T²) √(M² + T²) (1/2) × √(M² + T²) (1/2) × [M + √(M² + T²)] M + √(M² + T²) √(M² + T²) ANSWER DOWNLOAD EXAMIANS APP
Machine Design Shaft coupling is used in machinery to All of these Reduce the transmission of shock loads Introduce protection against over loads Introduce mechanical flexibility All of these Reduce the transmission of shock loads Introduce protection against over loads Introduce mechanical flexibility ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to Indian standard specifications, 100 H6/g5 means that Tolerance grade for the shaft is 4 to 8 and for the hole is 3 to 7 Tolerance grade for the hole is 4 to 8 and for the shaft is 3 to 7 Tolerance grade for the hole is 6 and for the shaft is 5 Tolerance grade for the shaft is 6 and for the hole is 5 Tolerance grade for the shaft is 4 to 8 and for the hole is 3 to 7 Tolerance grade for the hole is 4 to 8 and for the shaft is 3 to 7 Tolerance grade for the hole is 6 and for the shaft is 5 Tolerance grade for the shaft is 6 and for the hole is 5 ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to maximum normal stress theory, the maximum normal stress in the shaft is √(σ² × 4τ²) (1/2) × [σ + √(σ² × 4τ²)] σ + √(σ² × 4τ²) (1/2) × √(σ² × 4τ²) √(σ² × 4τ²) (1/2) × [σ + √(σ² × 4τ²)] σ + √(σ² × 4τ²) (1/2) × √(σ² × 4τ²) ANSWER DOWNLOAD EXAMIANS APP
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