Machine Design In a flange coupling, the bolts are subjected to Shear stress None of these Tensile stress Compressive stress Shear stress None of these Tensile stress Compressive stress ANSWER DOWNLOAD EXAMIANS APP
Machine Design A type of brake commonly used in motor cars is a Internal expanding brake Band brake Shoe brake Band and block brake Internal expanding brake Band brake Shoe brake Band and block brake ANSWER DOWNLOAD EXAMIANS APP
Machine Design A bolt of M 24 × 2 means that The pitch of the thread is 24 mm and depth is 2 mm The effective diameter of bolt is 24 mm and there are 2 threads per cm The nominal diameter of bolt is 24 mm and pitch is 2 mm Cross-sectional area of the threads is 24 mm² The pitch of the thread is 24 mm and depth is 2 mm The effective diameter of bolt is 24 mm and there are 2 threads per cm The nominal diameter of bolt is 24 mm and pitch is 2 mm Cross-sectional area of the threads is 24 mm² ANSWER DOWNLOAD EXAMIANS APP
Machine Design When two springs are in series (having stiffness K), the equivalent stiffness will be K K/2 K/4 2K K K/2 K/4 2K ANSWER DOWNLOAD EXAMIANS APP
Machine Design Factor of safety for fatigue loading is the ratio of Endurance limit to the working stress Young's modulus to the ultimate tensile strength Elastic limit to the working stress Elastic limit to the yield point Endurance limit to the working stress Young's modulus to the ultimate tensile strength Elastic limit to the working stress Elastic limit to the yield point ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα ANSWER DOWNLOAD EXAMIANS APP
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