Process Equipment and Plant Design Apex angle of conical heads used in the bottom heads of chemical process equipments is usually 60° 45° 75° 30° 60° 45° 75° 30° ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design For turbine agitator, the impeller diameter is about 0.65 to 0.85 d 0.1 to 0.2 d 0.3 to 0.5 d 0.95 d 0.65 to 0.85 d 0.1 to 0.2 d 0.3 to 0.5 d 0.95 d ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Rivets are generally specified by the Shank diameter Overall length None of these Head diameter Shank diameter Overall length None of these Head diameter ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design A certain pressure vessel manufacturer avoids doing reinforcements calculations for openings by always providing a reinforcing pad extending upto double the diameter of the opening and of the same material and thickness as that of the shell wall. If area compensation is accepted as a code guideline, his approach leads to safe design Only if the opening is on spherical vessel Only if the opening is on a vertical cylinderical vessel Only if the opening is on a horizontal cylinderical vessel Irrespective of the shape of the vessel Only if the opening is on spherical vessel Only if the opening is on a vertical cylinderical vessel Only if the opening is on a horizontal cylinderical vessel Irrespective of the shape of the vessel ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Filtration rate is affected by the Area of filtering surface & the viscosity of filtrate Pressure drop across the cake & filter medium Cake & filter medium resistance All of these Area of filtering surface & the viscosity of filtrate Pressure drop across the cake & filter medium Cake & filter medium resistance All of these ANSWER DOWNLOAD EXAMIANS APP
Process Equipment and Plant Design Heat transfer co-efficient, hG(Kcal/hr.m² .°C) and mass velocity of air, G (kg/hr.m² ) for air flow parallel to the surface in case of constant drying rate in batch drying is related as hG = 0.0176G0.8. But when the flow of air perpendicular to the surface is encountered, this equation changes to HG = 1.004G0.37 HG = 0.0176G0.37 0.0176G1.37 1.004G0.8 HG = 1.004G0.37 HG = 0.0176G0.37 0.0176G1.37 1.004G0.8 ANSWER DOWNLOAD EXAMIANS APP