Applied Mechanics and Graphic Statics An ordinate in a funicular polygon represents Equilibrium Shear force Resultant force Bending moment Equilibrium Shear force Resultant force Bending moment ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A solid sphere of mass M and radius R rolls down a plane inclined at 0 with the horizontal. The acceleration of sphere is (where g is acceleration due to gravity) (5/7) g sin0 (3/7) g sin 0 (2/5) g sin 0 (1/3) g sin0 (5/7) g sin0 (3/7) g sin 0 (2/5) g sin 0 (1/3) g sin0 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Centre of gravity of a thin hollow cone lies on the axis of symmetry at a height of One-third of the total height above base One-half of the total height above base None of these One-fourth of the total height above base One-third of the total height above base One-half of the total height above base None of these One-fourth of the total height above base ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A solid cylinder of mass M and radius R rolls down an inclined plane without slipping. The acceleration of center of mass of rolling cylinder is (where ‘g’ is acceleration due to gravity and 0 is inclination of plane with horizontal.) (1/3) g sinB (2/3) g sin 0 (2/3) g cos 9 g sin 9 (1/3) g sinB (2/3) g sin 0 (2/3) g cos 9 g sin 9 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The ratio of kinetic energy and potential energy of a simple harmonic oscillator, at a displacement equal to half its amplitude is given by 0.12569444444444 0.084027777777778 0.042361111111111 0.043055555555556 0.12569444444444 0.084027777777778 0.042361111111111 0.043055555555556 ANSWER DOWNLOAD EXAMIANS APP
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