SSC JE Electrical 2019 with solution SET-2 An ideal transformer will not transform?,I. PowerII. CurrentIII. FrequencyIV. Voltage II and III I and II Ill and IV I and III II and III I and II Ill and IV I and III ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-2 If ‘V’ is the voltage phasor and ‘I’ is the current phasor, then VI represents Total power Apparent power Active power Reactive power Total power Apparent power Active power Reactive power ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Apparent Power (S): It is defined as the product of r.m.s value of voltage (V) and current (1). It is denoted by S.S = V/I Volt Ampere
SSC JE Electrical 2019 with solution SET-2 Which of the following is the correct way of expressing the rating of a fuse? Volts Amperes Watts Ampere-hours Volts Amperes Watts Ampere-hours ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-2 The torque angle of a 3-phase synchronous motor depends on its _____ Supply voltage Speed Load Excitation Supply voltage Speed Load Excitation ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-2 In an alternator, if α = 60°, then find the pitch factor? 0 1 √3/2 1/2 0 1 √3/2 1/2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP The factor by which, the induced E.M.F gets reduced due to short pitching is called pitch factor or coil span factor denoted by Kc. It is given asKc = cosα/2givenα = 60°Kc = cos60/2Kc = cos30°Kc = √3/2
SSC JE Electrical 2019 with solution SET-2 The candle power of a lamp placed normal to a working plane is 60 CP. Find the distance if the illumination is 15 lux? 2.5 meters 1.5 meters 2 meters 4 meters 2.5 meters 1.5 meters 2 meters 4 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Candle Power of lamp = 60 CPIllumination of lamp = 15 luxDistance(D) = ? metersIllumination of lamp = (candle power)/(distance)2(D)2 = candle power/Illumination of lamp(D)2 = 60/15 =4D = √4D = 2
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