An alloy is made by mixing metal A costing Rs 2000/kg and metal B costing Rs 400/kg in the ratio A:B = 3:1. What is the cost (in Rs) of 8 kilograms of this alloy?

Alligation or Mixture problems
An alloy is made by mixing metal A costing Rs 2000/kg and metal B costing Rs 400/kg in the ratio A:B = 3:1. What is the cost (in Rs) of 8 kilograms of this alloy?

6400

9800

12800

1600

6400

9800

12800

1600

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Alligation or Mixture problems
The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is?

6 ml

11 ml

9 ml

15 ml

6 ml

11 ml

9 ml

15 ml

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Alligation or Mixture problems
From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is

118.08L

None of these

96L

81.92L

118.08L

None of these

96L

81.92L

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Alligation or Mixture problems
In what ratio must water be mixed with milk to gain 16⅔% on selling the mixture at cost price?

6 : 1

2 : 3

4 : 3

1 : 6

6 : 1

2 : 3

4 : 3

1 : 6

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Alligation or Mixture problems
In what ratio should milk and water be mixed so that after selling the mixture at the cost price a profit of 50/3 % is made?

2:3

1:2

2:5

6:1

2:3

1:2

2:5

6:1

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Method 1 to solve the equation.Let us assume Cost Price (C.P) of 1 liter milk be Y rupees.According to question,Selling Price (S.P) of 1 liter of mixture Y rupees. (Selling price should be same as Cost price)Profit = 50/3 %Let us assume Cost price of 1 Liter of Mixture of Water and Milk = CCost price of 1 Liter of Mixture of Water and Milk = Selling price of Mixture - Profit C = Y - C x 50/3%? C = Y - C x 50/3x100? C = Y - C x 1/3x2? C = Y - C/6? Y = C + C/6? Y = (6C + C)/6? Y = (6C + C)/6? Y = 7C/6? C = 6Y/7Since in Y rupees we will get 1 liter milk.Hence in 1 rupees we will get 1/Y liter milk.Hence in 6Y/7 rupees we will get 1 x 6Y/7 x Y liter milk.Hence in 6Y/7 rupees we will get 6/7 liter milk.We need 1 liter mixture of milk and water for sold on the same price, we need to mix the water.So water quantity in mixture = 1 - 6/7 = 1/7Ratio of Milk and water in mixture = quantity of Milk in Mixture/quantity of Water in MixtureRatio of Milk and water in mixture = 6/7 / 1/7Ratio of Milk and water in mixture = 6 x 7 / 7 Ratio of Milk and water in mixture = 6 / 1Ratio of Milk and water in mixture = 6 : 1Method 2 to solve the question.Let the original amount of milk be 1 liter and the cost price is 1 rupees per liter.Cost price of milk = 1 rupees.Selling price of Mixture = 1 rupees. When the milk is mix with x liters of water milk remaining is 1- x.Let us assume the cost price of milk in mixture is Y and given that the Sold Price is 1.we should use the Profit formula in algebra,Y + Y x 50/3 % = 1 Y + Y x 50/3 x 100 = 1Y + Y x /3 x 2 = 17Y/6 = 1Y = 6/7Y = 6/7 is the cost price of Mixture for 1 liter. Since water is free so there is not cost of water in mixture. So price of milk is 6/7 rs in mixture.Since as per question,In 1 rupees we will get 1 liter of milk.hence in 6/7 rupees we will get 1 x 6/7 = 6/7 liter of milk.Now we have to make 1 liter of mixture with water and milk.quantity of Water + Quantity of Milk = 1 literquantity of Water + 6/7 = 1 quantity of Water = 1 - 6/7 = (7 - 6)/7 quantity of Water = 1/7 Ratio of milk and Water = Quantity of Milk / quantity of Water Ratio of milk and Water = (6/7) / (1/7)Ratio of milk and Water = (6/7) x (7/1)Ratio of milk and Water = 6 x 7/ 7 x 1Ratio of milk and Water = 6 :1

Alligation or Mixture problems
In a mixture, the ratio of juice and water is 4 : 3. By adding 6 litre water the ratio of juice and water will be 8 : 7. What is the amount of juice in the original mixture?

48 lit

52 lit

96 lit

38 lit

48 lit

52 lit

96 lit

38 lit

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Alligation or Mixture problems

Alligation or Mixture problems An alloy is made by mixing metal A costing Rs 2000/kg and metal B costing Rs 400/kg in the ratio A:B = 3:1. What is the cost (in Rs) of 8 kilograms of this alloy?

Alligation or Mixture problems The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is?

Alligation or Mixture problems In what ratio must water be mixed with milk to gain 16⅔% on selling the mixture at cost price?

Alligation or Mixture problems In what ratio should milk and water be mixed so that after selling the mixture at the cost price a profit of 50/3 % is made?

Alligation or Mixture problems In a mixture, the ratio of juice and water is 4 : 3. By adding 6 litre water the ratio of juice and water will be 8 : 7. What is the amount of juice in the original mixture?

Alligation or Mixture problems
An alloy is made by mixing metal A costing Rs 2000/kg and metal B costing Rs 400/kg in the ratio A:B = 3:1. What is the cost (in Rs) of 8 kilograms of this alloy?

Alligation or Mixture problems
The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is?

Alligation or Mixture problems
In what ratio must water be mixed with milk to gain 16⅔% on selling the mixture at cost price?

Alligation or Mixture problems
In what ratio should milk and water be mixed so that after selling the mixture at the cost price a profit of 50/3 % is made?

Alligation or Mixture problems
In a mixture, the ratio of juice and water is 4 : 3. By adding 6 litre water the ratio of juice and water will be 8 : 7. What is the amount of juice in the original mixture?