Power Systems Advantages of shunt compensation is/are All of these It requires less maintanance smooth voltage regulation is possible by controlling excitation single unit can be used as both capacitance and inductor by adjusting the excitation All of these It requires less maintanance smooth voltage regulation is possible by controlling excitation single unit can be used as both capacitance and inductor by adjusting the excitation ANSWER DOWNLOAD EXAMIANS APP
Power Systems A 3-phase transmission line operating at Vs = 400 kV and has ABCD parameters A= D = 0.8∠0°, B = 100∠90° Ω, C = 0.5*10-6∠90° â„§. Find the no load receiving end voltage? 400 kV 500 kV 320 kv 600 kV 400 kV 500 kV 320 kv 600 kV ANSWER DOWNLOAD EXAMIANS APP
Power Systems How to find the total number of strands (N) when number of layers (x) are given Total number of strands N = 3x² - 3x - 1 Total number of strands N = 3x² + 3x - 1 Total number of strands N = 3x² - 3x + 1 Total number of strands N = 3x² + 3x + 1 Total number of strands N = 3x² - 3x - 1 Total number of strands N = 3x² + 3x - 1 Total number of strands N = 3x² - 3x + 1 Total number of strands N = 3x² + 3x + 1 ANSWER DOWNLOAD EXAMIANS APP
Power Systems At slack bus, which one of the following combinations of variables is not specified? Q and V V and δ P and Q P and V Q and V V and δ P and Q P and V ANSWER DOWNLOAD EXAMIANS APP
Power Systems The per unit value of a 2 ohm resistor at 100 MVA and 10 kV base voltage is 4 pu 2 pu 0.5 pu 0.2 pu 4 pu 2 pu 0.5 pu 0.2 pu ANSWER DOWNLOAD EXAMIANS APP
Power Systems The per unit impedance Z(pu) is given by ZΩ* (MVA)b/(KV)²b ZΩ* (MVA)b*100/(KV)²b ZΩ* (kVA)b/(KV)²b ZΩ* (MVA)b/((KV)²b *100) ZΩ* (MVA)b/(KV)²b ZΩ* (MVA)b*100/(KV)²b ZΩ* (kVA)b/(KV)²b ZΩ* (MVA)b/((KV)²b *100) ANSWER DOWNLOAD EXAMIANS APP