Machine Design According to Indian standards, total numbers of fundamental deviations are 25 10 20 15 25 10 20 15 ANSWER DOWNLOAD EXAMIANS APP
Machine Design According to maximum normal stress theory, the maximum normal stress in the shaft is (1/2) × [σ + √(σ² × 4τ²)] (1/2) × √(σ² × 4τ²) σ + √(σ² × 4τ²) √(σ² × 4τ²) (1/2) × [σ + √(σ² × 4τ²)] (1/2) × √(σ² × 4τ²) σ + √(σ² × 4τ²) √(σ² × 4τ²) ANSWER DOWNLOAD EXAMIANS APP
Machine Design If the centre distance of the mating gears having involute teeth is increased, then the pressure angle Remains unchanged Increases Decreases None of these Remains unchanged Increases Decreases None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design The effective stress in wire ropes during normal working is equal to the stress due to Acceleration/retardation of masses plus stress due to bending Axial load plus stress due to bending Axial load plus stress due to acceleration/retardation Bending plus stress due to acceleration/retardation Acceleration/retardation of masses plus stress due to bending Axial load plus stress due to bending Axial load plus stress due to acceleration/retardation Bending plus stress due to acceleration/retardation ANSWER DOWNLOAD EXAMIANS APP
Machine Design A steel containing up to 0.15% carbon is known as Mild steel High carbon steel Medium carbon steel Dead mild steel Mild steel High carbon steel Medium carbon steel Dead mild steel ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given by Where m = mass of belt per meter (kg/m) v = belt velocity (m/s) f = coefficient of friction a = angle of wrap (radians) (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα P1 / P2 = eᶠα P1 / P2 = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα ANSWER DOWNLOAD EXAMIANS APP
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