Hydraulics and Fluid Mechanics in ME A vertical wall is subjected to a pressure due to one kind of liquid, on one of its sides. The total pressure on the wall acts at a distance __________ from the liquid surface. 3H/4 H/2 H/3 2H/3 3H/4 H/2 H/3 2H/3 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The total head of a liquid particle in motion is equal to Kinetic head - (pressure head + potential head) Pressure head + kinetic head + potential head Potential head - (pressure head + kinetic head) Pressure head - (kinetic head + potential head) Kinetic head - (pressure head + potential head) Pressure head + kinetic head + potential head Potential head - (pressure head + kinetic head) Pressure head - (kinetic head + potential head) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The pitot tube is used to measure velocity at stagnation point static pressure dynamic pressure stagnation pressure velocity at stagnation point static pressure dynamic pressure stagnation pressure ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The flow in which conditions do not change with time at any point, is known as turbulent flow one dimensional flow steady flow uniform flow turbulent flow one dimensional flow steady flow uniform flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Discharge (Q) of a centrifugal pump is given by (where D = Diameter of impeller at inlet, b = Width of impeller at inlet, and Vf = Velocity of flow at inlet) Q = π.D.Vf Q = D.b.Vf Q = π.b.Vf Q = π.D.bf.V Q = π.D.Vf Q = D.b.Vf Q = π.b.Vf Q = π.D.bf.V ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular weir, considering the velocity of approach, is (whereH1 = H + Ha = Total height of water above the weir, H = Height of water over the crest of the weir, and Ha = Height of water due to velocity of approach) (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] (2/3) Cd × L. √2g [H13/2 - Ha3/2] (2/3) Cd × L.√2g [H1 - Ha] (2/3) Cd × L.√2g [H12 - Ha2] (2/3) Cd × L. √2g [H15/2 - Ha5/2] ANSWER DOWNLOAD EXAMIANS APP
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