Applied Mechanics and Graphic Statics A satellite moves in its orbit around the earth due to Gravitational force Centrifugal force Centripetal force None of these Gravitational force Centrifugal force Centripetal force None of these ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A flywheel of moment of inertia 20 kg.m is acted upon by a tangential force of 5 N at 2 m from its axis, for 3 seconds. The increase in angular velocity in radian per second is 3 2 43832 43892 3 2 43832 43892 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two forces are in equilibrium, then the forces must(i) Be equal in magnitude(ii) Be opposite in sense(iii) Act along the same line Only (i) (i) and (ii) All (i), (ii) and (iii) (i) and (iii) Only (i) (i) and (ii) All (i), (ii) and (iii) (i) and (iii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The acceleration of a train starting from rest at any instant is 1/6(V + 1) m/sec² where ‘V’ is the velocity of the train in m/sec. The train will attain a velocity of 36 km/hour after travelling a distance of 2000 m 2100 m 2300 m 2200 m 2000 m 2100 m 2300 m 2200 m ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The potential energy of a particle falling through a straight shaft drilled through the earth (assumed homogenous and spherical) is proportional to (where r is the distance of’the particle from centre of the earth) r r2 1/r log r r r2 1/r log r ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ ANSWER DOWNLOAD EXAMIANS APP
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