Chemical Reaction Engineering A reaction which is catalysed by an acid is also catalysed by any substance, which has a tendency to None of these Lose a proton Gain a proton Lose an electron None of these Lose a proton Gain a proton Lose an electron ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering Sometimes, batch process is preferred over continuous process, when the product Neither A nor B Both A & B Quality & yield can not be achieved in continuous processes, because of long residence time Sales demand is fluctuating Neither A nor B Both A & B Quality & yield can not be achieved in continuous processes, because of long residence time Sales demand is fluctuating ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering If the pore diffusion controls in a catalytic reaction, the apparent activation energy Ea is equal to ED/2 (E + ED) where ED is activation due to diffusion The intrinsic activation energy E (E + ED)/2 ED/2 (E + ED) where ED is activation due to diffusion The intrinsic activation energy E (E + ED)/2 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering For the liquid phase zero order irreversible reaction A → B, the conversion of A in a CSTR is found to be 0.3 at a space velocity of 0.1min⁻¹ . What will be the conversion for a PFR with a space velocity of 0.2 min⁻¹? Assume that all the other operating conditions are the same for CSTR and PFR. 0.15 0.9 0.3 0.6 0.15 0.9 0.3 0.6 ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering In which of the following gaseous phase reactions, the equilibrium of the reaction remains unaffacted by pressure changes ? N? + O? ? 2NO 2O? ? 3O? 2SO? + O? ? 2SO? 2NO? ? N?O? N? + O? ? 2NO 2O? ? 3O? 2SO? + O? ? 2SO? 2NO? ? N?O? ANSWER DOWNLOAD EXAMIANS APP
Chemical Reaction Engineering A first order gaseous phase reaction is catalysed by a non-porous solid. The kinetic rate constant and the external mass transfer co-efficients are k and kg respectively. The effective rate constant (keff) is given by 1/keff = 1/k + 1/kg keff = k + kg keff = (k+ kg)/2 keff = (kkg)1/2 1/keff = 1/k + 1/kg keff = k + kg keff = (k+ kg)/2 keff = (kkg)1/2 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS