Applied Mechanics and Graphic Statics A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is 30 sec 15 sec 20 sec 40 sec 30 sec 15 sec 20 sec 40 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball moving on a smooth horizontal table hits a rough vertical wall, the coefficient of restitution between ball and wall being 1/3. The ball rebounds at the same angle. The fraction of its kinetic energy lost is 43839 43864 43833 44052 43839 43864 43833 44052 ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The following is not a law of static friction: The force of friction always acts in a direction opposite to that in which the body tends to move The force of friction depends upon the roughness of the surface The magnitude of the limiting friction bears a constant ratio to the normal reaction between two surfaces The force of friction is dependent upon the area of contact The force of friction always acts in a direction opposite to that in which the body tends to move The force of friction depends upon the roughness of the surface The magnitude of the limiting friction bears a constant ratio to the normal reaction between two surfaces The force of friction is dependent upon the area of contact ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A ball of mass 250 g moving on a smooth horizontal table with a velocity of 10 m/sec hits an identical stationary ball ‘B’ on the table. If the impact is perfectly plastic, the velocity of the ball ‘B’ just after impact would be 10 m/sec None of these 5 m/sec Zero 10 m/sec None of these 5 m/sec Zero ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ e = v₂ - v₁/u₁ - u₂ e = u₂ - u₁/v₁ - v₂ e = v₁ - v₂/u₂ - u₁ e = v₁ - v₂/u₂ + u₁ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A force P of 50 N and another force Q of unknown magnitude act at 90° to each other. They are balanced by a force of 130 N. The magnitude of Q is 60 N 100 N 80 N 120 N 60 N 100 N 80 N 120 N ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS