Applied Mechanics and Graphic Statics A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is 15 sec 40 sec 30 sec 20 sec 15 sec 40 sec 30 sec 20 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics A stone was thrown vertically upwards from the ground with a velocity of 50 m/sec. After 5 seconds another stone was thrown vertically upwards from the same place. If both the stones strike the ground at the same time, then the velocity with which the second stone was thrown should be (Assume g = 10 m/sec²) 40 m/sec 50 m/sec 25 m/sec 15 m/sec 40 m/sec 50 m/sec 25 m/sec 15 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The total kinetic energy of a hoop of mass 2 kg and radius 4 m sliding with linear velocity 8 m/sec and angular velocity 5 radian/sec is 400 J 464 J 89 J 64 J 400 J 464 J 89 J 64 J ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The intrinsic equation of catenary is y = c cosh ψ S = c tan ψ y = c cosh x/c y = c sinh ψ y = c cosh ψ S = c tan ψ y = c cosh x/c y = c sinh ψ ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The graphical method of determining the forces in the members of a truss is based on Method of section Method of joint Either method None of the two methods Method of section Method of joint Either method None of the two methods ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics ‘u₁’ and ‘u₂’ are the velocities of approach of two moving bodies in the same direction and their corresponding velocities of separation are ‘v₁’ and ‘v₂’. As per Newton's law of collision of elastic bodies, the coefficient of restitution (e) is given by e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ e = v₁ - v₂/u₂ - u₁ e = u₂ - u₁/v₁ - v₂ e = v₂ - v₁/u₁ - u₂ e = v₁ - v₂/u₂ + u₁ ANSWER DOWNLOAD EXAMIANS APP
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