Applied Mechanics and Graphic Statics A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is 30 sec 15 sec 40 sec 20 sec 30 sec 15 sec 40 sec 20 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One Joule is equivalent to 1 dyne metre 9.81 Newton metre 1 kg wt metre 1 Newton metre 1 dyne metre 9.81 Newton metre 1 kg wt metre 1 Newton metre ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If two forces are in equilibrium, then the forces must (i) Be equal in magnitude (ii) Be opposite in sense (iii) Act along the same line Only (i) (i) and (iii) All (i), (ii) and (iii) (i) and (ii) Only (i) (i) and (iii) All (i), (ii) and (iii) (i) and (ii) ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the resultant of two forces has the same magnitude as either of the force, then the angle between the two forces is 60° 30° 45° 120° 60° 30° 45° 120° ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The piston of a steam engine moves with a simple harmonic motion. The crank rotates 120 r.p.m. and the stroke length is 2 meters. The linear velocity of the piston when it is at a distance of 0.5 metre from the centre, is 8.88 m/sec 10.88 m/sec 5.88 m/sec 12.88 m/sec 8.88 m/sec 10.88 m/sec 5.88 m/sec 12.88 m/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics When a body of mass M1 is hanging freely and another of mass M2 lying on a smooth inclined plane(α) are connected by a light index tensile string passing over a smooth pulley, the acceleration of the body of mass M1, will be given by g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M1 - M2 sin α)/(M1 + M2) m/sec² g(M2 × M1 sin α)/(M2 - M1) m/sec² g(M2 + M1 sin α)/(M1 + M2) m/sec² g(M1 + M2 sin α)/(M1 + M2) m/sec g(M1 - M2 sin α)/(M1 + M2) m/sec² ANSWER DOWNLOAD EXAMIANS APP
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