Applied Mechanics and Graphic Statics A particle moves with a velocity of 2 m/sec in a straight line with a negative acceleration of 0.1 m/sec2. Time required to traverse a distance of 1.5 m, is 30 sec 15 sec 40 sec 20 sec 30 sec 15 sec 40 sec 20 sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The bending moment in an arch is proportional to Vertical ordinate of funicular polygon Vertical ordinate of the arch None of these Intercept between the arch axis and the funicular polygon Vertical ordinate of funicular polygon Vertical ordinate of the arch None of these Intercept between the arch axis and the funicular polygon ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics If the linear velocity of a point on the rim of a wheel of 10 m diameter, is 50 m/sec, its angular velocity will be 10 rad/sec 20 rad/sec 5 rad/sec 20 rad/sec 10 rad/sec 20 rad/sec 5 rad/sec 20 rad/sec ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics One end of an elastic string of natural length / and modulus X is kept fixed while to the other end is attached a particle of mass m which is hanging freely under gravity. The particle is pulled down vertically through a distance x, held at rest and then released. The motion is None of these a rectilinear motion with constant speed a damped oscillatory motion a simple harmonic motion None of these a rectilinear motion with constant speed a damped oscillatory motion a simple harmonic motion ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics Pick up the incorrect statement from the following. In a simple harmonic motion Acceleration is zero at the mean position Velocity is maximum at its mean position Acceleration is minimum at the end of the stroke Velocity is minimum at the end of the stroke Acceleration is zero at the mean position Velocity is maximum at its mean position Acceleration is minimum at the end of the stroke Velocity is minimum at the end of the stroke ANSWER DOWNLOAD EXAMIANS APP
Applied Mechanics and Graphic Statics The intrinsic equation of catenary is S = c tan ψ y = c cosh x/c y = c sinh ψ y = c cosh ψ S = c tan ψ y = c cosh x/c y = c sinh ψ y = c cosh ψ ANSWER DOWNLOAD EXAMIANS APP
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