Alligation or Mixture problems
A jar full of whisky contains 40 % of alcohol. A part of this whisky is replaced by another containing 19 % alcohol and now the percentage of alcohol was found to be 26. The quantity of whisky replaced is ?
Let the initial amount of honey in the jar was K, then 512 = K 1 - 1 5 4 ? 20 % = 20 100 = 1 5 or 512 = K 4 5 4 Therefore, K = 1250 Hence initially the honey in the jar= 1.25 kg
Using Alligation rule, (Quantity of cheaper tea) / (Quantity of dearer tea) = (d - m) / (m - c) = 7/3Therefore, they must be mixed in the ratio of 7 : 3.