RCC Structures Design A continuous beam shall be deemed to be a deep beam if the ratio of effective span to overall depth, is Less than 2.5 2.5 Less than 2 2 Less than 2.5 2.5 Less than 2 2 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The angle of internal friction of soil mass is the angle whose None of these Sine is equal to the ratio of the maximum resistance to sliding on any internal inclined plane to the normal pressure acting on the plane Tangent is equal to the rate of the maximum resistance to sliding on any internal inclined plane to the normal pressure acting on the plane Cosine is equal to the ratio of the maximum resistance sliding on any internal inclined plane to the normal pressure acting on the plane None of these Sine is equal to the ratio of the maximum resistance to sliding on any internal inclined plane to the normal pressure acting on the plane Tangent is equal to the rate of the maximum resistance to sliding on any internal inclined plane to the normal pressure acting on the plane Cosine is equal to the ratio of the maximum resistance sliding on any internal inclined plane to the normal pressure acting on the plane ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The stresses developed in concrete and steel in reinforced concrete beam 25 cm width and 70 cm effective depth, are 62.5 kg/cm² and 250 kg/cm² respectively. If m = 15, the depth of its neutral axis is 35 cm 20 cm 25 cm 30 cm 35 cm 20 cm 25 cm 30 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The floor slab of a building is supported on reinforced cement floor beams. The ratio of the end and intermediate spans is kept 0.2 0.7 0.9 0.8 0.2 0.7 0.9 0.8 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design After pre-stressing process is completed, a loss of stress is due to Creep of concrete Shrinkage of concrete Elastic shortening of concrete All of the listed here Creep of concrete Shrinkage of concrete Elastic shortening of concrete All of the listed here ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) y = L/2 - (l - x̅) y = L/2 + (l - x̅) y = L/2 - (l + x̅) y = L - (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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