RL Circuits A 470Ω resistor and a coil with 125Ω inductive reactance are in parallel. Both components are across a 15 V ac voltage source. Current through the inductor is 12 mA 32 mA 120 mA 152 mA 12 mA 32 mA 120 mA 152 mA ANSWER DOWNLOAD EXAMIANS APP
RL Circuits The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is decreased increased doubled not a factor decreased increased doubled not a factor ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 angle 0° mA. The source voltage, expressed in polar form, is 3.84 angle 20.6° V 12.8 angle 20.6° V 13.84 angle 69.4° V 0.3 angle 20.6° V 3.84 angle 20.6° V 12.8 angle 20.6° V 13.84 angle 69.4° V 0.3 angle 20.6° V ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 1.2 kΩ resistor is in series with a 15 mH coil across a 10 kHz ac source. The magnitude of the total impedance is 152.6Ω 942Ω 1200Ω 1526Ω 152.6Ω 942Ω 1200Ω 1526Ω ANSWER DOWNLOAD EXAMIANS APP
RL Circuits When the resistor voltage in a series RL circuit becomes less than the inductor voltage, the phase angle cannot be determined increases decreases is not affected cannot be determined increases decreases is not affected ANSWER DOWNLOAD EXAMIANS APP
RL Circuits To increase the current in a series RL circuit, the frequency should be increased cannot be determined without values should be decreased should be constant should be increased cannot be determined without values should be decreased should be constant ANSWER DOWNLOAD EXAMIANS APP
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