RL Circuits A 3.3 kΩ resistor and a 120 mH coil are in parallel. Both components are across a 2 kHz, 12 V ac source. The total current in the circuit is 8.74 mA 8.74 A 874 A 874 mA 8.74 mA 8.74 A 874 A 874 mA ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 angle 0° mA. The source voltage, expressed in polar form, is 3.84 angle 20.6° V 0.3 angle 20.6° V 13.84 angle 69.4° V 12.8 angle 20.6° V 3.84 angle 20.6° V 0.3 angle 20.6° V 13.84 angle 69.4° V 12.8 angle 20.6° V ANSWER DOWNLOAD EXAMIANS APP
RL Circuits When the frequency of the voltage applied to a series RL circuit is increased, the phase angle does not change increases cannot be determined without values decreases does not change increases cannot be determined without values decreases ANSWER DOWNLOAD EXAMIANS APP
RL Circuits To increase the current in a series RL circuit, the frequency cannot be determined without values should be increased should be decreased should be constant cannot be determined without values should be increased should be decreased should be constant ANSWER DOWNLOAD EXAMIANS APP
RL Circuits Referring to Problem 23, the reactive power is 6.76 mVAR 100 mVAR 10 mVAR 148 mVAR 6.76 mVAR 100 mVAR 10 mVAR 148 mVAR ANSWER DOWNLOAD EXAMIANS APP
RL Circuits The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is doubled decreased increased not a factor doubled decreased increased not a factor ANSWER DOWNLOAD EXAMIANS APP
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