RL Circuits The voltages in Problem 5 are measured at a certain frequency. To make the resistor voltage less than the inductor voltage, the frequency is increased decreased not a factor doubled increased decreased not a factor doubled ANSWER DOWNLOAD EXAMIANS APP
RL Circuits If the frequency is halved and the resistance is doubled, the impedance of a series RL circuit remains constant cannot be determined without values doubles halves remains constant cannot be determined without values doubles halves ANSWER DOWNLOAD EXAMIANS APP
RL Circuits To increase the current in a series RL circuit, the frequency should be increased should be constant cannot be determined without values should be decreased should be increased should be constant cannot be determined without values should be decreased ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 12 kΩ resistor is in series with a 90 mH coil across an 8 kHz ac source. Current flow in the circuit, expressed in polar form, is I = 0.3 angle 0° mA. The source voltage, expressed in polar form, is 12.8 angle 20.6° V 0.3 angle 20.6° V 13.84 angle 69.4° V 3.84 angle 20.6° V 12.8 angle 20.6° V 0.3 angle 20.6° V 13.84 angle 69.4° V 3.84 angle 20.6° V ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 3.3 kΩ resistor and a 120 mH coil are in parallel. Both components are across a 2 kHz, 12 V ac source. The total current in the circuit is 8.74 A 874 A 874 mA 8.74 mA 8.74 A 874 A 874 mA 8.74 mA ANSWER DOWNLOAD EXAMIANS APP
RL Circuits A 470Ω resistor and a 200 mH coil are in parallel. Both components are across a 1.5 kHz ac source. The total admittance of the circuit, in polar form, is 12.18 angle 76° mS 12.60 angle –76° mS 12.18 angle –76° mS 218 angle –76° mS 12.18 angle 76° mS 12.60 angle –76° mS 12.18 angle –76° mS 218 angle –76° mS ANSWER DOWNLOAD EXAMIANS APP
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