Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 25/26 15/16 13/16 17/26 25/26 15/16 13/16 17/26 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Which of the following has most number of divisors? 99 176 182 101 99 176 182 101 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The L.C.M. of two numbers is 48. The numbers are in the ratio 2 : 3. Then sum of the number is: 10 20 40 30 10 20 40 30 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the numbers be 2x and 3x.Then, their L.C.M. = 6x.So, 6x = 48 or x = 8The numbers are 16 and 24.Hence, required sum = (16 + 24) = 40.
Problems on H.C.F and L.C.M The traffic lights at three different road crossings change after every 48 sec., 72 sec and 108 sec.respectively .If they all change simultaneously at 8:20:00 hours,then at what time they again change 10:13:17 hrs 7:25:14 hrs 8:27:12 hrs 9:22:08 hrs 10:13:17 hrs 7:25:14 hrs 8:27:12 hrs 9:22:08 hrs ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Interval of change = (L.C.M of 48,72,108)sec.=432sec. So, the lights will agin change simultaneously after every 432 seconds i.e,7 min.12sec Hence , next simultaneous change will take place at 8:27:12 hrs.
Problems on H.C.F and L.C.M Find the largest number of four digits exactly divisible by 12, 15, 18 and 27. 9720 8760 9620 8720 9720 8760 9620 8720 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. Aft 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds 26 minutes and 18 seconds 45 minutes 42 minutes and 36 seconds 46 minutes and 12 seconds ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 252, 308 and 198 = 2772.So, A, B and C will again meet at the starting point in 2772 sec. i.e., 46 min. 12 sec.
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