Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 17/26 25/26 15/16 13/16 17/26 25/26 15/16 13/16 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is: 1745 1045 364 777 1745 1045 364 777 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 6, 9, 15 and 18 is 90.Let required number be 90k + 4, which is multiple of 7.Least value of k for which (90k + 4) is divisible by 7 is k = 4.Required number = (90 x 4) + 4 = 364.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is: 23 22 21 24 23 22 21 24 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP L.C.M. of 5, 6, 4 and 3 = 60. On dividing 2497 by 60, the remainder is 37.Number to be added = (60 - 37) = 23.
Problems on H.C.F and L.C.M The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: 11115 15210 15110 15120 11115 15210 15110 15120 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The greatest number of five digits which is divisible by 32, 36, 40, 42 and 48 is: 90715 90730 90720 90725 90715 90730 90720 90725 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find the other number ? 99 100 97 98 99 100 97 98 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Product of two numbers= HCF x LCM 77 x a = 11 x 693Other number a = (11×693)/77 = 99.
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