Problems on H.C.F and L.C.M 1095/1168 when expressed in simplest form is: 15/16 25/26 13/16 17/26 15/16 25/26 13/16 17/26 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Product of two co-prime numbers is 117. Their L.C.M should be: F 1 Cannot be calculated 117 equal to their H. F 1 Cannot be calculated 117 equal to their H. ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M The least number of five digits that have 144 their HCF is? 10070 10080 10075 10085 10070 10080 10075 10085 ANSWER DOWNLOAD EXAMIANS APP
Problems on H.C.F and L.C.M Find the smallest number of five digits exactly divisible by 16,24,36 and 54. 10468 10268 10368 10568 10468 10268 10368 10568 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Smallest number of five digits is 10000. Required number must be divisible by L.C.M. of 16,24,36,54 i.e 432, On dividing 10000 by 432,we get 64 as remainder. Required number = 10000 +( 432 – 64 ) = 10368.
Problems on H.C.F and L.C.M 252 can be expressed as a product of primes as: 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 2 x 2 x 2 x 3 x 7 2 x 2 x 3 x 3 x 7 3 x 3 x 3 x 3 x 7 2 x 3 x 3 x 3 x 7 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Clearly, 252 = 2 x 2 x 3 x 3 x 7.
Problems on H.C.F and L.C.M The least number which should be added to 2497 so that the sum is exactly divisible by 5,6,4 and 3 is : 33 3 13 23 33 3 13 23 ANSWER DOWNLOAD EXAMIANS APP
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