Fractions and Decimals 0.15 / (0.5 / 15) = ? 40.5 4.5 None of these 400.5 40.5 4.5 None of these 400.5 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let Y = 0.15 / (0.5 / 15) = (15/100) / [(5/100) / 15) = 4.5
Fractions and Decimals 0.6 + 0.66 + 0.066 + 6.606 = ? 7.932 7932 79.32 793.2 7.932 7932 79.32 793.2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.6 + 0.66 + 0.066 + 6.606= 0.600 + 0.660 + 0.066 + 6.660= 7.932
Fractions and Decimals The value of [(0.96)³- (0.1)³] / [(0.96)² + 0.096 + (0.1)²] is : 0.56 0.46 0.86 0.36 0.56 0.46 0.86 0.36 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression=[(0.96)³ - (0.1)³] / [(0.96)² + (0.96 x 0.1) + (0.1)²]= [(a³ - b³) / (a² + ab + b²)] = (a - b)= (0.96 - 0.1)= 0.86
Fractions and Decimals The expression (11.98 * 11.98 + 11.98 * (x) + 0.02 * 0.02) will be a perfect square for x equal to : 4 0.4 None of these 0.04 4 0.4 None of these 0.04 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given = (11.98)^2 + (0.02)^2 + 11.98 * x. For the given expression to be a perfect square, we must have11.98 * x = 2 * 11.98 * 0.02=> x = 0.04
Fractions and Decimals The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.3 2013 2011 2012 2014 2013 2011 2012 2014 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Suppose commodity X wil cost 40 paise more than Y after Z years.Then, (4.20 + 0.40Z) - (6.30 + 0.15Z) = 0.40 0.25Z = 0.40 + 2.10 Z= X will cost 40 paise more than Y 10 years after 2001 . i.e in 2011
Fractions and Decimals In the year 2011, Shantanu gets a total of Rs. 3832.5 as his pocket allowance. Find his pocket allowance per day.? Rs. 1000.50 Rs. 100.50 Rs. 1.50 Rs. 10.50 Rs. 1000.50 Rs. 100.50 Rs. 1.50 Rs. 10.50 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Allowance per day = 3832.5 / 365 = Rs. 10.50
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