Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = E/R = Y/F M/I = R/E = F/Y M/I = E/R = F/Y I/M = R/E = F/Y M/I = E/R = Y/F M/I = R/E = F/Y M/I = E/R = F/Y I/M = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be 5/8 3/2 8/5 2/3 5/8 3/2 8/5 2/3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A compound bar consists of two bars of equal length. Steel bar cross -section is 3500 mm²and that of brass bar is 3000 mm². These are subjected to a compressive load 100,000 N. If Eb = 0.2 MN/mm² and Eb = 0.1 MN/mm², the stresses developed are: b = 10 N/mm² s = 20 N/mm 2 b = 5 N/mm² s = 10 N/mm² b = 6 N/mm² s = 12 N/mm² b = 8 N/mm² s = 16 N/mm² b = 10 N/mm² s = 20 N/mm 2 b = 5 N/mm² s = 10 N/mm² b = 6 N/mm² s = 12 N/mm² b = 8 N/mm² s = 16 N/mm² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Gradually applied static loads do not change with time their Magnitude All of these Direction Point of application Magnitude All of these Direction Point of application ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel plate d × b is sandwiched rigidly between two timber joists each D × B/2 in section. The steel will be (where Young’s modulus of steel is m times that of the timber). BD² + mbd²)/6D] BD² + mbd³)/4D] BD³ + mbd³)/6D] BD² + mbd²)/4D] BD² + mbd²)/6D] BD² + mbd³)/4D] BD³ + mbd³)/6D] BD² + mbd²)/4D] ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The greatest load which a spring can carry without getting permanently distorted, is called Proof stress Proof load Stiffness Proof resilience Proof stress Proof load Stiffness Proof resilience ANSWER DOWNLOAD EXAMIANS APP
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