Chemical Engineering Thermodynamics When a gas in a vessel expands, its internal energy decreases. The process involved is Adiabatic Isothermal Reversible Irreversible Adiabatic Isothermal Reversible Irreversible ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics __________ calorimeter is normally used for measuring the dryness fraction of steam, when it is very low. Throttling A combination of separating & throttling Bucket Separating Throttling A combination of separating & throttling Bucket Separating ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Law of corresponding states says that The surface of separation (i. e. the meniscus) between liquid and vapour phase disappears at the critical temperature , two different gases behave similarly, if their reduced properties (i.e. P, V and T) are same The molar heat of energy of gas at constant volume should be nearly constant (about 3 calories) No gas can be liquified above the critical temperature, howsoever high the pressure may be The surface of separation (i. e. the meniscus) between liquid and vapour phase disappears at the critical temperature , two different gases behave similarly, if their reduced properties (i.e. P, V and T) are same The molar heat of energy of gas at constant volume should be nearly constant (about 3 calories) No gas can be liquified above the critical temperature, howsoever high the pressure may be ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Efficiency of a heat engine working on Carnot cycle between two temperature levels depends upon the Two temperatures only Mass and pressure both of the working fluid Mass of the working fluid Pressure of working fluid Two temperatures only Mass and pressure both of the working fluid Mass of the working fluid Pressure of working fluid ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Which of the following identities can be most easily used to verify steam table data for superheated steam. (∂V/∂T)P = -(∂S/∂P)T (∂T/∂P)S = (∂V/∂S)P (∂T/∂V)S = (∂p/∂S)V (∂P/∂T)V = (∂S/∂V)T (∂V/∂T)P = -(∂S/∂P)T (∂T/∂P)S = (∂V/∂S)P (∂T/∂V)S = (∂p/∂S)V (∂P/∂T)V = (∂S/∂V)T ANSWER DOWNLOAD EXAMIANS APP
Chemical Engineering Thermodynamics Boiling of liquid is accompanied with increase in the Vapor pressure All of these Specific entropy Specific Gibbs free energy Vapor pressure All of these Specific entropy Specific Gibbs free energy ANSWER DOWNLOAD EXAMIANS APP
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