C Programming What's wrong in the following statement, provided k is a variable of type int?for(k = 2, k <=12, k++) The variable k can’t be initialized. The increment should always be ++k . The variable must always be the letter i when using a for loop. There should be a semicolon at the end of the statement. The commas should be semicolons. The variable k can’t be initialized. The increment should always be ++k . The variable must always be the letter i when using a for loop. There should be a semicolon at the end of the statement. The commas should be semicolons. ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine the Final Output:void main(){ printf("\nab"); printf("\bsi"); printf("\rha");} asiha hai absiha haasi asiha hai absiha haasi ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char *str1 = "abcd"; char str2[] = "abcd"; printf("%d %d %d", sizeof(str1), sizeof(str2), sizeof("abcd"));} 2 4 5 2 5 5 5 5 5 2 4 4 2 4 5 2 5 5 5 5 5 2 4 4 ANSWER DOWNLOAD EXAMIANS APP
C Programming String concatenation means - Comparing the two strings to define the larger one. Merging two strings. Partitioning the string into two strings. Extracting a substring out of a string. Combining two strings. Comparing the two strings to define the larger one. Merging two strings. Partitioning the string into two strings. Extracting a substring out of a string. Combining two strings. ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the program?#include#define int char void main(){ int i = 65; printf("sizeof(i)=%d", sizeof(i));} None of These Compiler Error sizeof(i)=1 sizeof(i)=2 None of These Compiler Error sizeof(i)=1 sizeof(i)=2 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ printf("%p", main);} make an infinite loop None of These Error Some address will be printed make an infinite loop None of These Error Some address will be printed ANSWER DOWNLOAD EXAMIANS APP
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