C Programming What will happen after compiling and running following code?main(){ printf("%p", main); } Error None of these. Some address will be printed. Will make an infinite loop. Error None of these. Some address will be printed. Will make an infinite loop. ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine output:void main(){ int i=10; i = !i>14; printf("i=%d", i); } 14 None of these 10 1 0 14 None of these 10 1 0 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ char *p; p="Hello"; printf("%c", *&*p);} Some Address will be printed H None of These Hello Some Address will be printed H None of These Hello ANSWER DOWNLOAD EXAMIANS APP
C Programming The declarationint (*p) [5];means None of these. p is a pointer to a 5 elements integer array. p is one dimensional array of size 5, of pointers to integers. The same as int *p[ None of these. p is a pointer to a 5 elements integer array. p is one dimensional array of size 5, of pointers to integers. The same as int *p[ ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine the Final Output:void main(){ printf("\nab"); printf("\bsi"); printf("\rha");} asiha absiha hai haasi asiha absiha hai haasi ANSWER DOWNLOAD EXAMIANS APP
C Programming What does the following declaration mean?int (*ptr)[10]; ptr is an pointer to array ptr is an array of 10 integers ptr is array of pointers to 10 integers ptr is a pointer to an array of 10 integers ptr is an pointer to array ptr is an array of 10 integers ptr is array of pointers to 10 integers ptr is a pointer to an array of 10 integers ANSWER DOWNLOAD EXAMIANS APP
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