Let 'N' is the smallest number which divided by 13 and 16 leaves respective remainders of 2 and 5.Required number = (LCM of 13 and 16) - (common difference of divisors and remainders) = (208) - (11) = 197.
Let the no. be xTherefore 68x / 100 - 35x / 100 = 1216 Therefore x = 1216 x 100 / 33Therefore 28% of x = 28x / 100 = 1216 x 100 / 33 x 28 / 100= 1216 x 100 x 28 / 33 x 1/100 = 1031.75
EXAMIANS