Fractions and Decimals What should be subtracted from the multiplication of 0.527 and 2.013 to get 1 ? 0.060851 6085.1 60.851 None of these 0.060851 6085.1 60.851 None of these ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ∵ 0.527 x 2.013 = 1.060851Hence, the required number = 1.060851 - 1 = 0.060851.
Fractions and Decimals A person was asked to state his age in years. His reply was , "Take my age 3 years hence, multiply it by 3 and subtract 3 times my age 3 years ago and you will know how old I am." What was the age of 16 17 19 18 16 17 19 18 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the present age of person be x years.Then, 3(x + 3) - 3(x - 3 ) = x <=> (3x + 9) - (3x - 9) = x <=> x = 18
Fractions and Decimals (.356 x .365 - 2 x .365 x .106 + .106 x .106) / (.632 x .632 + 2 x .632 x .368 +.368 x .368) = ? 6.25 .0625 62.5 .625 6.25 .0625 62.5 .625 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression = [(.356)² -2 x .356 x .106 + (.106)²] / [(.632)²+2 x .632 x .368 +(.368)²]= (a² -2ab + b²) / (c²+2cd+d²)= (a - b)² / (c + d)²= (.356 -.106)² / (.632 + .368)²= (.25)² = .0625
Fractions and Decimals (.58 x .58 x .58 - .42 x .42 x .42 - 3 x .58 x .42 x .16) = ? 0.004096 0.04096 4.096 0.4096 0.004096 0.04096 4.096 0.4096 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given Expression = (.53)³ - (.42)³- 3 x .58 x .42 x (.58-.42)= a³-b³ -3ab(a - b) = (a - b)³(where a = .58 and b=.42)= (.58 - .42 )³ = .16 x .16 x .16 = 0.004096
Fractions and Decimals The value of [(0.96)³- (0.1)³] / [(0.96)² + 0.096 + (0.1)²] is : 0.56 0.36 0.46 0.86 0.56 0.36 0.46 0.86 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given expression=[(0.96)³ - (0.1)³] / [(0.96)² + (0.96 x 0.1) + (0.1)²]= [(a³ - b³) / (a² + ab + b²)] = (a - b)= (0.96 - 0.1)= 0.86
Fractions and Decimals If 0.12 ÷ x² = 12, than x = ? 0.01 10 0.1 0.001 0.01 10 0.1 0.001 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP 0.12 ÷ x² = 12 => 0.12/x² = 12=> x² = 0.12/12 = 0.01 => x = 0.1
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