C Programming What number would be shown on the screen after the following statements of C are executed?char ch; int i; ch = 'G'; i = ch-'A';printf("%d", i); 7 6 8 5 9 7 6 8 5 9 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ int i=0, j=0; if(i && j++) printf("%d..%d", i++, j); printf("%d..%d", i, j);} 0..1 1..1 0..0 1..0 0..1 1..1 0..0 1..0 ANSWER DOWNLOAD EXAMIANS APP
C Programming Determine Output:void main(){ int i=10; i=!i>14; printf("i=%d", i);} 10 0 14 1 10 0 14 1 ANSWER DOWNLOAD EXAMIANS APP
C Programming In an expression involving || operator, evaluationI. Will be stopped if one of its components evaluates to falseII. Will be stopped if one of its components evaluates to trueIII. Takes place from right to leftIV. Takes place from left to right III and IV II and IV II and III I and III I and II III and IV II and IV II and III I and III I and II ANSWER DOWNLOAD EXAMIANS APP
C Programming What will be the output of the given program?#includevoid main(){int value1, value2=100, num=100;if(value1=value2%5) num=5;printf("%d %d %d", num, value1, value2);} 5 0 100 100 5 100 5 0 20 100 0 100 100 100 100 5 0 100 100 5 100 5 0 20 100 0 100 100 100 100 ANSWER DOWNLOAD EXAMIANS APP
C Programming Comment on the following pointer declaration?int *ptr, p; ptr is pointer to integer, p may or may not be. ptr and p, both are pointers to integer. ptr and p both are not pointers to integer. ptr is a pointer to integer, p is not. ptr is pointer to integer, p may or may not be. ptr and p, both are pointers to integer. ptr and p both are not pointers to integer. ptr is a pointer to integer, p is not. ANSWER DOWNLOAD EXAMIANS APP
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