JAVA Array
What is the output of the following code?public class Test{ public static void main(String args[]){ double[] myList = {1, 5, 5, 5, 5, 1}; double max = myList[0]; int indexOfMax = 0; for(int i = 1; i < myList.length; i++){ if(myList[i] > max){ max = myList[i]; indexOfMax = i; } } System.out.println(indexOfMax); }}

3
2
1
0
4

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JAVA Array
What would be the result of attempting to compile and run the following code?public class HelloWorld{ public static void main(String[] args){ double[] x = new double[]{1, 2, 3}; System.out.println("Value is " + x[1]); }}

The program has a compile error because the syntax new double[]{1, 2, 3} is wrong and it should be replaced by new double[3]{1, 2, 3};
The program has a compile error because the syntax new double[]{1, 2, 3} is wrong and it should be replaced by {1, 2, 3}.
The program has a compile error because the syntax new double[]{1, 2, 3} is wrong and it should be replaced by new double[]{1.0, 2.0, 3.0};
The program compiles and runs fine and the output

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JAVA Array
What will be the output?public class Test{ public static void main(String[] args){ int[] x = new int[3]; System.out.println("x[0] is " + x[0]); }}

The program has a compile error because the size of the array wasn't specified when declaring the array.
The program has a runtime error because the array element x[0] is not defined.
The program runs fine and displays x[0] is 0.
The program has a runtime error because the array elements are not initialized.

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JAVA Array
Analyze the following code and choose the correct answer.int[] arr = new int[5];arr = new int[6];

The code has runtime errors because the variable arr cannot be changed once it is assigned.
The code can compile and run fine. The second line assigns a new array to arr.
The code has compile errors because the variable arr cannot be changed once it is assigned.
The code has compile errors because we cannot assign a different size array to arr.

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