Engineering Economics What is normally used to compare alternatives that accomplish the same purpose but have unequal lives? Annual cost method Present worth method MARR Capitalized cost method Annual cost method Present worth method MARR Capitalized cost method ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics If ‘P’ is principal amount, ‘I’ is the rate of interest per annum and ‘n’ is the number of periods in years, the compound amount factor (CAF) is: (1 + i)(1/2n) None of these √(n + i) (1 + i)n (1 + i)(1/2n) None of these √(n + i) (1 + i)n ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics A young engineer borrowed P 10,000 at 12% interest and paid P 2,000 per annum for the last 4 years. What does he have to pay at the end of the fifth year in order to pay off his loan? P 6,292.93 P 6,222.39 P 6,922.93 P 6,999.39 P 6,292.93 P 6,222.39 P 6,922.93 P 6,999.39 ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics What refers to the residual value of a company’s assets after all outside liabilities (shareholders excluded) have been allowed for? Par value Return Dividend Equity Par value Return Dividend Equity ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics A type of bond to which are attached coupons indicating the interest due and the date when such interest is to be paid is called ______. Collateral trust bond Coupon bond Mortgage bond Registered bond Collateral trust bond Coupon bond Mortgage bond Registered bond ANSWER DOWNLOAD EXAMIANS APP
Engineering Economics The owner of the construction company makes use of the estimate: To assist in financial arrangements To determine economic feasibility of the project All of these To determine the capital investment costs To assist in financial arrangements To determine economic feasibility of the project All of these To determine the capital investment costs ANSWER DOWNLOAD EXAMIANS APP